8086 program to find the square root of a perfect square root number | Set-2

Prerequisite – 8086 program to find Square Root of a number Problem – Write a program to find the square root of a perfect number where starting address for code is 2000 and number is stored at 3000 memory address and store result into 3002 memory address. Example – Algorithm –

1. Move 0000 to register CX immediately
2. Move value of memory 3000 into register BX
3. Move CX into AX
4. Multiply value of accumulator with CX
5. Compare AX with BX
6. Jump if zero to step
7. Increase CX register by 1
8. Jump if no zero to step 3
9. Move content of register CX into memory 3002
10. Stop

Program –

Memory	Mnemonics	Operands	Comment
2000	MOV	CX, 0000	[CX] <- 0000
2003	MOV	BX, [3000]	[BX] <- [3000]
2007	MOV	AX, CX	[AX] <- [CX]
2009	MUL	CX	[AX] <- [AX] * [CX]
200B	CMP	AX, BX	[AX] – [BX]
200D	JZ	2015	Jump if zero
2010	INC	CX	[CX] <- [CX] + 1
2012	JNZ	2007	Jump if not zero
2015	MOV	[3002], CX	[3002] <- CX
2019	HLT		Stop

Explanation – Registers AX, BX, CX, are used for general purpose.

1. MOV is used to transfer the data
2. INC is used to increase given register by 1
3. JNZ is used to jump to the given step if there is no zero
4. JZ is used to jump to the given step if there is zero
5. MUL is used to multiply value of AX with the given register
6. CMP is used to compare the value of two registers
7. HLT is used to halt the program

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