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Check a number is odd or even without modulus operator
  • Difficulty Level : Easy
  • Last Updated : 06 May, 2021

Given a number, check whether it is even or odd.

Examples : 

Input: n = 11
Output: Odd

Input: n = 10
Output: Even
 

Method 1: Using Loop. 
The idea is to start with a boolean flag variable as true and switch it n times. If flag variable gets original value (which is true) back, then n is even. Else n is false.

Below is the implementation of this idea.  

C++




// A simple C++ program to check for
// even or odd
#include <iostream>
using namespace std;
 
// Returns true if n is even, else odd
bool isEven(int n)
{
    bool isEven = true;
    for (int i=1;  i <= n; i++)
        isEven = !isEven;
    return isEven;
}
 
// Driver code
int main()
{
    int n = 101;
    isEven(n) ? cout << "Even" : cout << "Odd";
    return 0;
}

Java




// A simple Java program to
// check for even or odd
 
class GFG {
     
    // Returns true if n
    // is even, else odd
    static boolean isEven(int n)
    {
        boolean isEven = true;
         
        for (int i = 1; i <= n; i++)
            isEven = !isEven;
             
        return isEven;
    }
     
     
    // Driver Code
    public static void main(String args[])
    {
         
        int n = 101;
        if(isEven(n))
            System.out.println("Even");
        else
            System.out.println("Odd");
         
    }
}
 
// This code is contributed by Sam007

Python3




# A simple Python program to
# check for even or odd
 
# Returns true if n is even,
# else odd
def isEven(n):
    isEven = True;
    for i in range(1, n+1):
        if isEven == True:
            isEven = False;
        else:
            isEven = True;
 
    return isEven;
 
# Driver code   
n = 101;
if isEven(n) == True:
    print ("Even");
else:
    print ("Odd");
     
# This code is contributed by
# Manish Shaw (manishshaw1)

C#




// A simple C# program to check for
// even or odd
using System;
 
public class GFG {
     
    // Returns true if n is even,
    // else odd
    static bool isEven(int n)
    {
        bool isEven = true;
         
        for (int i = 1; i <= n; i++)
            isEven = !isEven;
             
        return isEven;
    }
     
    // Driver code
    public static void Main()
    {
        int n = 101;
        if(isEven(n))
            Console.Write("Even");
        else
            Console.Write("Odd");
    }
}
 
// This code is contributed by Sam007.

PHP




<?php
// A simple PHP program to check for
// even or odd
 
// Returns true if n is even,
// else odd
function isEven($n)
{
    $isEven = true;
    for ($i = 1; $i <= $n; $i++)
        $isEven = !$isEven;
    return $isEven;
}
 
    // Driver code
    $n = 101;
    $is=isEven($n) ? "Even" : "Odd";
    echo "$is"
 
// This code is contributed by ajit
?>

Javascript




<script>
 
// A simple Javascript program to check
// for even or odd
 
// Returns true if n is even,
// else odd
function isEven(n)
{
    let isEven = true;
       
    for(let i = 1; i <= n; i++)
        isEven = !isEven;
           
    return isEven;
}
 
// Driver code
let n = 101;
if (isEven(n))
    document.write("Even");
else
    document.write("Odd");
     
// This code is contributed by mukesh07
 
</script>
Output: 



Odd

 

Method 2: By multiply and divide by 2. Divide the number by 2 and multiply by 2 if the result is same as input then it is an even number else it is an odd number.

C++




// A simple C++ program to check for
// even or odd
#include <iostream>
using namespace std;
 
// Returns true if n is even, else odd
bool isEven(int n)
{
    // Return true if n/2 does not result
    // in a float value.
    return ((n / 2) * 2 == n);
}
 
// Driver code
int main()
{
    int n = 101;
    isEven(n) ? cout << "Even" : cout << "Odd";
    return 0;
}

Java




// A simple Java program
// to check for even or odd
 
class GFG {
     
// Returns true if n
// is even, else odd
static boolean isEven(int n)
{
     
    // Return true if
    // n/2 does not result
    // in a float value.
    return ((n / 2) * 2 == n);
}
 
// Driver code
public static void main(String[] args)
{
    int n = 101;
    if(isEven(n) != false)
        System.out.print( "Even" );
    else
        System.out.print( "Odd" );
}
}
 
// This code is contributed by
// Smitha Dinesh Semwal.

Python3




# A simple Python 3 program
# to check for even or odd
 
# Returns true if n
# is even, else odd
def isEven(n):
 
     
    # Return true if
    # n/2 does not result
    # in a float value.
    return (int(n / 2) * 2 == n)
 
 
# Driver code
n = 101
if(isEven(n) != False):
    print("Even")
else:
    print("Odd")
 
# This code is contributed by
# Smitha Dinesh Semwal.

C#




// A simple C# program
// to check for even or odd
using System;
class GFG {
     
// Returns true if n
// is even, else odd
static bool isEven(int n)
{
     
    // Return true if
    // n/2 does not result
    // in a float value.
    return ((n / 2) * 2 == n);
}
 
// Driver code
public static void Main(String[] args)
{
    int n = 101;
    if(isEven(n) != false)
        Console.Write("Even");
    else
        Console.Write("Odd");
}
}
 
// This code is contributed by
// Smitha Dinesh Semwal.

PHP




<?php
// A simple PHP program to
// check for even or odd
 
// Returns true if n
// is even, else odd
function isEven($n)
{
    // Return true if n/2
    // does not result
    // in a float value.
    return ((int)($n / 2) * 2 == $n);
}
 
// Driver code
$n = 101;
if(isEven($n))
    echo ("Even");
else
    echo ("Odd");
     
// This code is contributed by
// Manish Shaw (manishshaw1)
?>

Javascript




<script>
 
// A simple Javascript program to
// check for even or odd
 
// Returns true if n is even,
// else odd
function isEven(n)
{
     
    // Return true if n/2 does not result
    // in a float value.
    return (parseInt(n / 2, 10) * 2 == n);
}
 
// Driver code
let n = 101;
isEven(n) ? document.write("Even") :
            document.write("Odd");
             
// This code is contributed by divyeshrabadiya07
 
</script>
Output : 
Odd

 

Method 3: Using Bitwise operator &. 
A better solution is to use bitwise operators. We need to check whether last bit is 1 or not. If last bit is 1 then the number is odd, otherwise always even.

Explanation: 

 input : 5    // odd
   00000101              
 & 00000001                
--------------                
   00000001       
--------------

input : 8     //even
   00001000              
 & 00000001                 
--------------               
   00000000        
--------------

Below is the implementation of the idea. 

C++




// A simple C++ program to check for
// even or odd
#include <iostream>
using namespace std;
 
// Returns true if n is even, else odd
bool isEven(int n)
{
    // n&1 is 1, then odd, else even
    return (!(n & 1));
}
 
// Driver code
int main()
{
    int n = 101;
    isEven(n) ? cout << "Even" : cout << "Odd";
    return 0;
}

Java




// A simple Java program to check for
// even or odd
import java.io.*;
import java.util.*;
 
public class GFG {
      
    // Returns 0 if n
    // is even, else odd
    static int isEven(int n)
    {
          
        // n&1 is 1, then
        // odd, else even
        return (n & 1);
    }
      
    // Driver code
    public static void main(String args[])
    {
        int n = 101;
        if(isEven(n)==0)
            System.out.print("Even");
        else
            System.out.print("Odd");
    }
}
  
// This code is contributed
// by Manish Shaw (manishshaw1)

Python3




# A simple Python program to
# check for even or odd
# Returns 0 if n
# is even, else odd
def isEven(n) :
      
    # n&1 is 1, then
    # odd, else even
    return (n & 1);
  
# Driver code
n = 101;
if(isEven(n) == 0) :
    print ("Even");
else :
    print ("Odd");
      
# This code is contributed
# by Manish Shaw (manishshaw1)

C#




// A simple C# program to check for
// even or odd
using System;
using System.Collections.Generic;
 
class GFG {
     
    // Returns 0 if n
    // is even, else odd
    static int isEven(int n)
    {
         
        // n&1 is 1, then
        // odd, else even
        return (n & 1);
    }
     
    // Driver code
    public static void Main()
    {
        int n = 101;
        if(isEven(n)==0)
            Console.Write("Even");
        else
            Console.Write("Odd");
    }
}
 
// This code is contributed
// by Manish Shaw (manishshaw1)

PHP




<?php
// A simple PHP program to
// check for even or odd
// Returns 0 if n
// is even, else odd
function isEven($n)
{
     
    // n&1 is 1, then
    // odd, else even
    return ($n & 1);
}
 
// Driver code
$n = 101;
if(isEven($n) == 0)
    echo ("Even");
else
    echo ("Odd");
     
// This code is contributed
// by Manish Shaw (manishshaw1)
?>
Output : 
Odd

 

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