A computer has the following CPIs for instruction types A, B, C, D, and a program P3 has the following mix of instructions,
INSTRUCTION TYPE |
Cycle per Instruction |
FREQUENCY |
A |
1.7 |
22% |
B |
2.1 |
29% |
C |
2.7 |
17% |
D |
2.4 |
32% |
What will be the average CPI for given above system?
(A) 2.21
(B) 3.6
(C) 1.57
(D) 2.4
Answer: (A)
Explanation: Average cycle per instruction (CPI),
= Σ(CPIi * ICi)
= (1.7 * 0.22 + 2.1 * 0.29 + 2.7 * 0.17 + 2.4 * 0.32)
= 2.21
SO, option (A) is correct.
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