The Boolean theorem AB + A\’C + BC = AB + A\’C corresponds to
(A) (A + B) ∙ (A\’ + C) ∙ (B + C) = (A + B) ∙ (A\’ + C)
(B) AB + A\’C + BC = AB + BC
(C) AB + A\’C + BC = (A + B) ∙ ( A \’+ C) ∙ (B + C)
(D) (A + B) ∙ (A\’ + C) ∙ (B + C) = AB + A\’C
Answer: (A)
Explanation:
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