The function AB’C + A’BC + ABC’ + A’B’C + AB’C’ is equivalent to
(A) AC’+AB+A’C
(B) AB’+AC’+A’C
(C) A’B+AC’+AB’
(D) A’B+AC+AB’


Answer: (B)

Explanation:
(A\’BC + A\’B\’C) + (ABC\’ + AB\’C\’) + AB\’C
A\’C(B + B\’) + AC\'(B + B\’) + AB\’C
A\’C * 1 + AC\’ * 1 + AB\’C
A\’C + AC\’ + AB\’C
A\’C + A(C\’ + B\’C)
A\’C + A(C\’ + B\’)
A\’C + AC\’ + AB\’

 
Thus, option (B) is correct.

 
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