If P, Q, R are Boolean variables, then (P + Q\’)(PQ\’ + PR)(P\’R\’ + Q\’) simplifies (P+\\overline{Q})(P.\\overline{Q} + P.R)(\\overline{P}.\\overline{R}+\\overline{Q}) = (P+Q)(P.Q + P.R.\\overline{Q}) = (P+Q)(P.\\overline{Q})[\\because (1+R)=1] = P\\overline{Q} (A) PQ\’ (B) PR\’ (C) PQ\’ + R (D) PR\’\’ + Q

Answer: (A)

Explanation:  (P+\\overline{Q})(P.\\overline{Q} + P.R)(\\overline{P}.\\overline{R}+\\overline{Q})  = (P+Q)(P.Q + P.R.\\overline{Q})  = (P+Q)(P.\\overline{Q})[\\because (1+R)=1]  = P\\overline{Q}

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  • Last Updated : 19 Nov, 2018

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