Last Updated : 19 Nov, 2018

A byte addressable computer has a memory capacity of 2m KB( kbytes ) and can perform 2m operations. An instruction involving 3 operands and one operator needs maximum of

(A) 3m bits
(B) 3m + n bits
(C) m + n bits
(D) none of the above


Answer: (D)

Explanation:

Quiz of this Question


Share your thoughts in the comments