Last Updated :
19 Nov, 2018
A byte addressable computer has a memory capacity of 2m KB( kbytes ) and can perform 2m operations. An instruction involving 3 operands and one operator needs maximum of
(A) 3m bits
(B) 3m + n bits
(C) m + n bits
(D) none of the above
Answer: (D)
Explanation:
Quiz of this Question
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