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Write your own strcmp that ignores cases

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Write a modified strcmp function which ignores cases and returns -1 if s1 < s2, 0 if s1 = s2, else returns 1. For example, your strcmp should consider “GeeksforGeeks” and “geeksforgeeks” as same string.
Source: Microsoft Interview Set 5
Following solution assumes that characters are represented using ASCII representation, i.e., codes for ‘a’, ‘b’, ‘c’, … ‘z’ are 97, 98, 99, … 122 respectively. And codes for ‘A’, “B”, ‘C’, … ‘Z’ are 65, 66, … 90 respectively. 
Following are the detailed steps. 
1) Iterate through every character of both strings and do following for each character. 
a) If str1[i] is same as str2[i], then continue. 
b) If inverting the 6th least significant bit of str1[i] makes it same as str2[i], then continue. For example, if str1[i] is 65, then inverting the 6th bit will make it 97. And if str1[i] is 97, then inverting the 6th bit will make it 65. 
c) If any of the above two conditions is not true, then break. 
2) Compare the last (or first mismatching in case of not same) characters. 
 

C++




#include <bits/stdc++.h>
using namespace std;
/* implementation of strcmp that ignores cases */
int ic_strcmp(string s1, string s2)
{
    int i;
    for (i = 0; s1[i] && s2[i]; ++i)
    {
        /* If characters are same or inverting the
        6th bit makes them same */
        if (s1[i] == s2[i] || (s1[i] ^ 32) == s2[i])
        continue;
        else
        break;
    }
 
    /* Compare the last (or first mismatching in
    case of not same) characters */
    if (s1[i] == s2[i])
        return 0;
 
    // Set the 6th bit in both, then compare
    if ((s1[i] | 32) < (s2[i] | 32))
        return -1;
    return 1;
}
 
// Driver program to test above function
int main()
{
    cout<<"ret: "<<ic_strcmp("Geeks", "apple") <<endl;
    cout<<"ret: "<<ic_strcmp("", "ABCD")<<endl;
    cout<<"ret: "<<ic_strcmp("ABCD", "z")<<endl;
    cout<<"ret: "<<ic_strcmp("ABCD", "abcdEghe")<<endl;
    cout<<"ret: "<<ic_strcmp("GeeksForGeeks", "gEEksFORGeEKs")<<endl;
    cout<<"ret: "<<ic_strcmp("GeeksForGeeks", "geeksForGeeks")<<endl;
    return 0;
}
 
//This code is contributed by rathbhupendra


C




#include <stdio.h>
 
/* implementation of strcmp that ignores cases */
int ic_strcmp(char *s1, char *s2)
{
    int i;
    for (i = 0; s1[i] && s2[i]; ++i)
    {
        /* If characters are same or inverting the
           6th bit makes them same */
        if (s1[i] == s2[i] || (s1[i] ^ 32) == s2[i])
           continue;
        else
           break;
    }
 
    /* Compare the last (or first mismatching in
       case of not same) characters */
    if (s1[i] == s2[i])
        return 0;
 
    // Set the 6th bit in both, then compare
    if ((s1[i] | 32) < (s2[i] | 32))
        return -1;
    return 1;
}
 
// Driver program to test above function
int main(void)
{
    printf("ret: %d\n", ic_strcmp("Geeks", "apple"));
    printf("ret: %d\n", ic_strcmp("", "ABCD"));
    printf("ret: %d\n", ic_strcmp("ABCD", "z"));
    printf("ret: %d\n", ic_strcmp("ABCD", "abcdEghe"));
    printf("ret: %d\n", ic_strcmp("GeeksForGeeks", "gEEksFORGeEKs"));
    printf("ret: %d\n", ic_strcmp("GeeksForGeeks", "geeksForGeeks"));
    return 0;
}


Java




// Java program for the above approach
 
import java.util.*;
 
public class Main {
    /* implementation of strcmp that ignores cases */
    public static int ic_strcmp(String s1, String s2) {
        int i;
        for (i = 0; i < s1.length() && i < s2.length(); ++i) {
            /* If characters are same or inverting the 6th bit makes them same */
            if (s1.charAt(i) == s2.charAt(i) || (s1.charAt(i) ^ 32) == s2.charAt(i))
                continue;
            else
                break;
        }
 
        /* Compare the last (or first mismatching in case of not same) characters */
        if (i == s1.length() && i == s2.length())
            return 0;
 
        // Set the 6th bit in both, then compare
        if (i == s1.length())
            return -1;
        else if (i == s2.length())
            return 1;
        else if ((s1.charAt(i) | 32) < (s2.charAt(i) | 32))
            return -1;
        return 1;
    }
 
    // Driver program to test above function
    public static void main(String[] args) {
        System.out.println("ret: " + ic_strcmp("Geeks", "apple"));
        System.out.println("ret: " + ic_strcmp("", "ABCD"));
        System.out.println("ret: " + ic_strcmp("ABCD", "z"));
        System.out.println("ret: " + ic_strcmp("ABCD", "abcdEghe"));
        System.out.println("ret: " + ic_strcmp("GeeksForGeeks", "gEEksFORGeEKs"));
        System.out.println("ret: " + ic_strcmp("GeeksForGeeks", "geeksForGeeks"));
    }
}
 
 
// This code is contributed by codebraxnzt


Python3




# Python implementation of above approach
 
# implementation of strcmp that ignores cases
def ic_strcmp(s1, s2):
    i = 0
    while i < len(s1) and i < len(s2):
       
        # If characters are same or inverting the 6th bit makes them same
        if s1[i] == s2[i] or ord(s1[i]) ^ 32 == ord(s2[i]):
            i += 1
        else:
            break
             
    # Compare the last (or first mismatching in case of not same) characters
    if i == len(s1) and i == len(s2):
        return 0
    elif i == len(s1):
        return -1
    elif i == len(s2):
        return 1
    # Set the 6th bit in both, then compare
    if ord(s1[i]) | 32 < ord(s2[i]) | 32:
        return -1
    return 1
 
# Driver program to test above function
if __name__ == '__main__':
    print("ret: ", ic_strcmp("Geeks", "apple"))
    print("ret: ", ic_strcmp("", "ABCD"))
    print("ret: ", ic_strcmp("ABCD", "z"))
    print("ret: ", ic_strcmp("ABCD", "abcdEghe"))
    print("ret: ", ic_strcmp("GeeksForGeeks", "gEEksFORGeEKs"))
    print("ret: ", ic_strcmp("GeeksForGeeks", "geeksForGeeks"))
 
 
# This code is contributed by codebraxnzt


C#




using System;
 
public class GFG{
 
    static int IcStrCmp(string s1, string s2)
    {
        int i;
 
        for (i = 0; i < s1.Length && i < s2.Length; ++i)
        {
            if (char.ToLower(s1[i]) == char.ToLower(s2[i]))
            {
                continue;
            }
            else
            {
                break;
            }
        }
 
        if (i == s1.Length && i == s2.Length)
        {
            return 0;
        }
 
        if (i == s1.Length)
        {
            return -1;
        }
        else if (i == s2.Length)
        {
            return 1;
        }
        else if (char.ToLower(s1[i]) < char.ToLower(s2[i]))
        {
            return -1;
        }
 
        return 1;
    }
 
    static void Main(string[] args)
    {
        Console.WriteLine("ret: " + IcStrCmp("Geeks", "apple"));
        Console.WriteLine("ret: " + IcStrCmp("", "ABCD"));
        Console.WriteLine("ret: " + IcStrCmp("ABCD", "z"));
        Console.WriteLine("ret: " + IcStrCmp("ABCD", "abcdEghe"));
        Console.WriteLine("ret: " + IcStrCmp("GeeksForGeeks", "gEEksFORGeEKs"));
        Console.WriteLine("ret: " + IcStrCmp("GeeksForGeeks", "geeksForGeeks"));
    }
}


Javascript




// Javascript program for the above approach
 
// implementation of strcmp that ignores cases
function ic_strcmp(s1, s2) {
  let i = 0;
  while (i < s1.length && i < s2.length) {
    // If characters are same or inverting the 6th bit makes them same
    if (s1[i] === s2[i] || (s1.charCodeAt(i) ^ 32) === s2.charCodeAt(i)) {
      i += 1;
    } else {
      break;
    }
  }
 
  // Compare the last (or first mismatching in case of not same) characters
  if (i === s1.length && i === s2.length) {
    return 0;
  } else if (i === s1.length) {
    return -1;
  } else if (i === s2.length) {
    return 1;
  }
 
  // Set the 6th bit in both, then compare
  if ((s1.charCodeAt(i) | 32) < (s2.charCodeAt(i) | 32)) {
    return -1;
  }
  return 1;
}
 
// Driver program to test above function
console.log("ret: ", ic_strcmp("Geeks", "apple"));
console.log("ret: ", ic_strcmp("", "ABCD"));
console.log("ret: ", ic_strcmp("ABCD", "z"));
console.log("ret: ", ic_strcmp("ABCD", "abcdEghe"));
console.log("ret: ", ic_strcmp("GeeksForGeeks", "gEEksFORGeEKs"));
console.log("ret: ", ic_strcmp("GeeksForGeeks", "geeksForGeeks"));
 
// This code is contributed by adityashatmfh


Output

ret: 1
ret: -1
ret: -1
ret: -1
ret: 0
ret: 0


Time Complexity: O(min(|s1|, |s2|))

Auxiliary Space: O(1)

This article is compiled by Narendra Kangralkar.
 



Last Updated : 02 Nov, 2023
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