stable_sort() is used to sort the elements in the range [first, last) in ascending order. It is like std::sort, but stable_sort() keeps the relative order of elements with equivalent values. It comes under the <algorithm> header file.
Syntax:
template< class RandomIterator>
void stable_sort( RandomIterator first, RandomIterator last );
or
template< class RandomIterator, class Compare>
void stable_sort( RandomIterator first, RandomIterator last, Compare comp );
Parameters:
- first: iterator pointing to the first element in the range.
- last: iterator pointing to the past last element in the range.
- comp: predicate function that accepts two arguments and returns true if the two arguments are in order and false otherwise.
Return Value: It returns nothing.
Example:
CPP
#include <bits/stdc++.h>
using namespace std;
struct Interval {
int start, end;
};
bool compareInterval(Interval i1, Interval i2)
{
return (i1.start < i2.start);
}
int main()
{
Interval arr[]
= { { 1, 3 }, { 2, 4 }, { 1, 7 }, { 2, 19 } };
int n = sizeof (arr) / sizeof (arr[0]);
stable_sort(arr, arr + n, compareInterval);
cout << "Intervals sorted by start time : \n" ;
for ( int i = 0; i < n; i++)
cout << "[" << arr[i].start << ", " << arr[i].end
<< "] " ;
return 0;
}
|
Output
Array after sorting using stable_sort is :
0 1 2 3 4 5 6 7 8 9
How to Sort in Descending Order using stable_sort()?
Like sort(), stable_sort() takes a third parameter that is used to specify the order in which elements are to be sorted. We can pass “greater()” function to sort in decreasing order. This function does comparison in a way that puts greater element before.
Syntax:
// arr is the array and n is the size
stable_sort(arr, arr + n, greater<int>());
Example:
Output
Array after sorting :
9 8 7 6 5 4 3 2 1 0
When to Prefer stable_sort over sort()?
Sometime we want to make sure that order of equal elements is same in sorted array as it was in original array. This can be useful if these values have associated other fields. For example,
- Consider sorting students by marks, if two students have the same marks, we may want to keep them in the same order as they appear input. Please refer to stability in sorting algorithms for details.
- Consider we have time intervals sorted by ending time and we want to sort by start time. Also, if two start times are same, we want to keep them sorted by the end time. This is not guaranteed by sort().
CPP
#include <bits/stdc++.h>
using namespace std;
struct Interval {
int start, end;
};
bool compareInterval(Interval i1, Interval i2)
{
return (i1.start < i2.start);
}
int main()
{
Interval arr[]
= { { 1, 3 }, { 2, 4 }, { 1, 7 }, { 2, 19 } };
int n = sizeof (arr) / sizeof (arr[0]);
stable_sort(arr, arr + n, compareInterval);
cout << "Intervals sorted by start time : \n" ;
for ( int i = 0; i < n; i++)
cout << "[" << arr[i].start << ", " << arr[i].end
<< "] " ;
return 0;
}
|
Output
Intervals sorted by start time :
[1, 3] [1, 7] [2, 4] [2, 19]
Difference Between sort and stable_sort()
Key
|
sort()
|
stable_sort()
|
Implementation |
sort() function usually uses Introsort. Therefore, sort() may preserve the physical order of semantically equivalent values but can’t be guaranteed. |
stable_sort() function usually uses mergesort. Therefore, stable_sort() preserve the physical order of semantically equivalent values and its guaranteed. |
Time Complexity |
It is O(n*log(n)). |
It is O(n*log^2(n)).
If additional memory linearly proportional to length is not available. If its available then O(n*log(n)).
|
Last Updated :
23 Dec, 2021
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