**1) What is the output of the following program?
**

L = list('123456') L[0] = L[5] = 0 L[3] = L[-2] print(L)

a) [0, ‘2’, ‘3’, ‘4’, ‘5’, 0]

b) [‘6’, ‘2’, ‘3’, ‘5’, ‘5’, ‘6’]

c) [‘0’, ‘2’, ‘3’, ‘5’, ‘5’, ‘0’]

d) [0, ‘2’, ‘3’, ‘5’, ‘5’, 0]

**Ans. (d)**

**Explanation: ** L[0] is ‘1’ and L[5] is ‘6’, both of these elements will be replaced by 0 in the List. L[3], which is 4 will be replaced L[-2] i.e. 5.

**2) What is the output of the following program?**

T = tuple('geeks') a, b, c, d, e = T b = c = '*' T = (a, b, c, d, e) print(T)

a) (‘g’, ‘*’, ‘*’, ‘k’, ‘s’)

b) (‘g’, ‘e’, ‘e’, ‘k’, ‘s’)

c) (‘geeks’, ‘*’, ‘*’)

d) KeyError

**Ans. (a)**

**Explanation: ** A tuple is created as T = (‘g’, ‘e’, ‘e’, ‘k’, ‘s’), then it is unpacked into a, b, c, d and e, mapping from ‘g’ to a and ‘s’ to e. b and c which are both ‘e’ are equal to ‘*’ and then the existing tuple is replaced by packing a, b, c, d and e into a tupple T.

**3) What is the value of L at the end of execution of the following program?**

L = [2e-04, 'a', False, 87] T = (6.22, 'boy', True, 554) for i in range(len(L)): if L[i]: L[i] = L[i] + T[i] else: T[i] = L[i] + T[i] break

a) [6.222e-04, ‘aboy’, True, 641]

b) [6.2202, ‘aboy’, 1, 641]

c) [6.2202, ‘aboy’, True, 87]

d) [6.2202, ‘aboy’, False, 87]

**Ans. (d)**

**Explanation: ** The for loop will run for i = 0 to i = 3, i.e. 4 times(len(L) = 4). 2e-04 is same as 0.0002, thus L[i] = 6.22 + 0.0002 = 6.2202. String addition will result in concatenation, ‘a’ + ‘boy’ = ‘aboy’. False + True is True, it’ll return the integer value of 1. As tuples are immutable, the code will end with TypeError, but elements of L will be updated.

**4) What is the output of the following program?**

T = (2e-04, True, False, 8, 1.001, True) val = 0 for x in T: val += int(x) print(val)

a) 12

b) 11

c) 11.001199999999999

d) TypeError

**Ans. (b)**

**Explanation: ** Integer value of 2e-04(0.0002) is 0, True holds a value 1 and False a 0, integer value of 1.001 is 1. Thus total 0 + 1 + 0 + 8 + 1 + 1 = 11.

**5) Which of the options below could possibly be the output of the following program?**

L = [3, 1, 2, 4] T = ('A', 'b', 'c', 'd') L.sort() counter = 0 for x in T: L[counter] += int(x) counter += 1 break print(L)

a) [66, 97, 99, 101]

b) [66, 68, 70, 72]

c) [66, 67, 68, 69]

d) ValueError

**Ans. (d)**

**Explanation:** After sort(L), L will be = [1, 2, 3, 4]. Counter = 0, L[0] i.e. 1, x = ‘A’, but Type Conversion of char ‘A’ to integer will throw error and the value cannot be stored in L[0], thus a ValueError.

This article is contributed by **Piyush Doorwar**. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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