What is the least number which when divided by 4, 5, 6 and 7 leaves a remainder 3, but when divided by 9 leaves no remainder?
Question 10-Explanation:
LCM of 4,5,6,7 is 420
=>(420k+3) should be divisible by 9
if k =1, 423/9, remainder=0
When 423 is divided by 4, 5, 6, 7, it gives remainder 3 and when divided by 9 leaves a remainder 0.
So, the least number which when divided by 4, 5, 6 and 7 leaves a remainder 3, but when divided by 9 leaves no remainder is 423