- Courses
- Tutorials
- Jobs
- Practice
- Contests
Interview Preparation
- Interview Preparation For Software Developers
- Must Coding Questions - Company-wise
- Must Do Coding Questions - Topic-wise
- Company-wise Practice Problems
- Company Preparation
- Competitive Programming
- Software Design-Patterns
- Company-wise Interview Experience
- Experienced - Interview Experiences
- Internship - Interview Experiences
Commerce
- Commerce
- Class 11 Accountancy Notes
- Class 12 Accountancy Notes
- Accountancy
- Class 11 Business Studies Notes
- Class 12 Business Studies Notes
- Business Studies
- Class 11 Microeconomics Notes
- Class 11 Statistics For Economics Notes
- Class 12 Macroeconomics Notes
- Class 12 Indian Economic Development Notes
- Economics
- Management
- Income Tax
- Finance
GATE | GATE-CS-2007 | Question 54
In a simplified computer the instructions are:
The computer has only two registers, and OP is either ADD or SUB. Consider the following basic block:
Assume that all operands are initially in memory. The final value of the computation should be in memory. What is the minimum number of MOV instructions in the code generated for this basic block?
![GATECS2007Q54]("http://www.geeksforgeeks.org/wp-content/uploads/gq/2014/02/GATECS2007Q54.png")
The computer has only two registers, and OP is either ADD or SUB. Consider the following basic block:
![GATECS2007Q541]("http://www.geeksforgeeks.org/wp-content/uploads/gq/2014/02/GATECS2007Q541.png")
Assume that all operands are initially in memory. The final value of the computation should be in memory. What is the minimum number of MOV instructions in the code generated for this basic block?(A)
2
(B)
3
(C)
5
(D)
6
Answer
Please comment below if you find anything wrong in the above post
Feeling lost in the world of random DSA topics, wasting time without progress? It's time for a change! Join our DSA course, where we'll guide you on an exciting journey to master DSA efficiently and on schedule.
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 geeks!
Last Updated :
Share your thoughts in the comments
GeeksforGeeks