# Find elements larger than half of the elements in an array

Given an array of n elements, the task is to find the elements that are greater than half of elements in an array. In case of of odd elements, we need to print elements larger than floor(n/2) elements where n is total number of elements in array.

Examples:

```Input :  arr[] = {1, 6, 3, 4}
Output : 4 6

Input  :  arr[] = {10, 4, 2, 8, 9}
Output :  10 9 8
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

A naive approach is to take an element and compare with all other elements and if it is greater then increment the count and then check if count is greater than n/2 elements then print.

An efficient method is to sort the array in ascending order and then print last ceil(n/2) elements from sorted array.

Below is C++ implementation of this sorting based approach.

## C/C++

```// C++ program to find elements that are larger than
// half of the elements in array
#include <bits/stdc++.h>
using namespace std;

// Prints elements larger than n/2 element
void findLarger(int arr[], int n)
{
// Sort the array in ascending order
sort(arr, arr + n);

// Print last ceil(n/2) elements
for (int i = n-1; i >= n/2; i--)
cout << arr[i] << " ";
}

// Driver program
int main()
{
int arr[] = {1, 3, 6, 1, 0, 9};
int n = sizeof(arr)/sizeof(arr[0]);
findLarger(arr, n);
return 0;
}
```

## Java

```// Java program to find elements that are
// larger than half of the elements in array
import java.util.*;

class Gfg
{
// Prints elements larger than n/2 element
static void findLarger(int arr[], int n)
{
// Sort the array in ascending order
Arrays.sort(arr);

// Print last ceil(n/2) elements
for (int i = n-1; i >= n/2; i--)
System.out.print(arr[i] + " ");
}

// Driver program
public static void main(String[] args)
{
int arr[] = {1, 3, 6, 1, 0, 9};
int n = arr.length;
findLarger(arr, n);
}
}

// This code is contributed by Raghav Sharma
```

## Python

```# Python program to find elements that are larger than
# half of the elements in array
# Prints elements larger than n/2 element
def findLarger(arr,n):

# Sort the array in ascending order
x = sorted(arr)

# Print last ceil(n/2) elements
for i in range(n/2,n):
print(x[i]),

# Driver program
arr = [1, 3, 6, 1, 0, 9]
n = len(arr);
findLarger(arr,n)

# This code is contributed by Afzal Ansari
```

Output:

```9 6 3
```

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