Convert given time into words

1

Given a time in the format of hh:mm (12-hour format) 0 < hh < 12, 0 <= mm < 60. The task is to convert it into words as shown:

Examples:

Input : h = 5, m = 0
Output : five o' clock

Input : h = 6, m = 24
Output : twenty four minutes past six

Corner cases are m = 0, m = 15, m = 30 and m = 45.

6:00 six o'clock
6:10 ten minutes past six
6:15 quarter past six
6:30 half past six
6:45 quarter to seven
6:47 thirteen minutes to seven

The idea is to use if-else-if statement to determine the time in words. According to above given example, on the basis of minutes we can categories time in words into 8, that are minutes equal to 0, 15, 30, 45, 1, 59 and in range less than 30 or greater than 30. Check the value of minutes and print accordinly.

Below is C++ implementation of this approach:

// C++ program to convert time into words
#include <bits/stdc++.h>
using namespace std;

// Print Time in words.
void printWords(int h, int m)
{
    char nums[][64] = { "zero", "one", "two", "three", "four",
                        "five", "six", "seven", "eight", "nine",
                        "ten", "eleven", "twelve", "thirteen",
                        "fourteen", "fifteen", "sixteen", "seventeen",
                        "eighteen", "nineteen", "twenty", "twenty one",
                        "twenty two", "twenty three", "twenty four",
                        "twenty five", "twenty six", "twenty seven",
                        "twenty eight", "twenty nine",
                      };

    if (m == 0)
        printf("%s o' clock\n", nums[h]);

    else if (m == 1)
        printf("one minute past %s\n", nums[h]);

    else if (m == 59)
        printf("one minute to %s\n", nums[(h % 12) + 1]);

    else if (m == 15)
        printf("quarter past %s\n", nums[h]);

    else if (m == 30)
        printf("half past %s\n", nums[h]);

    else if (m == 45)
        printf("quarter to %s\n", nums[(h % 12) + 1]);

    else if (m <= 30)
        printf("%s minutes past %s\n", nums[m], nums[h]);

    else if (m > 30)
        printf("%s minutes to %s\n", nums[60 - m],
                                     nums[(h % 12) + 1]);
}

// Driven Program
int main()
{
    int h = 6;
    int m = 24;

    printWords(h, m);
    return 0;
}

Output:

twenty four minutes past six

This article is contributed by Anuj Chauhan. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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