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Convert a Binary Tree into Doubly Linked List in spiral fashion

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Given a Binary Tree, convert it into a Doubly Linked List where the nodes are represented Spirally. The left pointer of the binary tree node should act as a previous node for created DLL and the right pointer should act as the next node. 

The solution should not allocate extra memory for DLL nodes. It should use binary tree nodes for creating DLL i.e. only change of pointers is allowed.

For example, for the tree on the left side, Doubly Linked List can be,
1 2 3 7 6 5 4 8 9 10 11 13 14 or
1 3 2 4 5 6 7 14 13 11 10 9 8.

We strongly recommend you minimize your browser and try this yourself first.

We can do this by doing a spiral order traversal in O(n) time and O(n) extra space. The idea is to use deque (Double-ended queue) that can be expanded or contracted on both ends (either its front or it’s back). We do something similar to level order traversal but to maintain spiral order, for every odd level, we dequeue node from the front and insert its left and right children in the back of the deque data structure. And for each even level, we dequeue node from the back and insert its right and left children in the front of the deque. We also maintain a stack to store Binary Tree nodes. Whenever we pop nodes from deque, we push that node into the stack. 

Later, we pop all nodes from the stack and push the nodes at the beginning of the list. We can avoid the use of stack if we maintain a tail pointer that always points to the last node of DLL and inserts nodes in O(1) time in the end.

Below is the implementation of the above idea 

C++




/* c++ program to convert Binary Tree into Doubly
   Linked List where the nodes are represented
   spirally. */
#include <bits/stdc++.h>
using namespace std;
  
// A Binary Tree Node
struct Node
{
    int data;
    struct Node *left, *right;
};
  
/* Given a reference to the head of a list and a node,
inserts the node on the front of the list. */
void push(Node** head_ref, Node* node)
{
    // Make right of given node as head and left as
    // NULL
    node->right = (*head_ref);
    node->left = NULL;
  
    // change left of head node to given node
    if ((*head_ref) !=  NULL)
        (*head_ref)->left = node ;
  
    // move the head to point to the given node
    (*head_ref) = node;
}
  
// Function to prints contents of DLL
void printList(Node *node)
{
    while (node != NULL)
    {
        cout << node->data << " ";
        node = node->right;
    }
}
  
/* Function to print corner node at each level */
void spiralLevelOrder(Node *root)
{
    // Base Case
    if (root == NULL)
        return;
  
    // Create an empty deque for doing spiral
    // level order traversal and enqueue root
    deque<Node*> q;
    q.push_front(root);
  
    // create a stack to store Binary Tree nodes
    // to insert into DLL later
    stack<Node*> stk;
  
    int level = 0;
    while (!q.empty())
    {
        // nodeCount indicates number of Nodes
        // at current level.
        int nodeCount = q.size();
  
        // Dequeue all Nodes of current level and
        // Enqueue all Nodes of next level
        if (level&1)    //odd level
        {
            while (nodeCount > 0)
            {
                // dequeue node from front & push it to
                // stack
                Node *node = q.front();
                q.pop_front();
                stk.push(node);
  
                // insert its left and right children
                // in the back of the deque
                if (node->left != NULL)
                    q.push_back(node->left);
                if (node->right != NULL)
                    q.push_back(node->right);
  
                nodeCount--;
            }
        }
        else      //even level
        {
            while (nodeCount > 0)
            {
                // dequeue node from the back & push it
                // to stack
                Node *node = q.back();
                q.pop_back();
                stk.push(node);
  
                // inserts its right and left children
                // in the front of the deque
                if (node->right != NULL)
                    q.push_front(node->right);
                if (node->left != NULL)
                    q.push_front(node->left);
                nodeCount--;
            }
        }
        level++;
    }
  
    // head pointer for DLL
    Node* head = NULL;
  
    // pop all nodes from stack and
    // push them in the beginning of the list
    while (!stk.empty())
    {
        push(&head, stk.top());
        stk.pop();
    }
  
    cout << "Created DLL is:\n";
    printList(head);
}
  
// Utility function to create a new tree Node
Node* newNode(int data)
{
    Node *temp = new Node;
    temp->data = data;
    temp->left = temp->right = NULL;
  
    return temp;
}
  
// Driver program to test above functions
int main()
{
    // Let us create binary tree shown in above diagram
    Node *root =  newNode(1);
    root->left = newNode(2);
    root->right = newNode(3);
    root->left->left = newNode(4);
    root->left->right = newNode(5);
    root->right->left = newNode(6);
    root->right->right = newNode(7);
  
    root->left->left->left  = newNode(8);
    root->left->left->right  = newNode(9);
    root->left->right->left  = newNode(10);
    root->left->right->right  = newNode(11);
    //root->right->left->left  = newNode(12);
    root->right->left->right  = newNode(13);
    root->right->right->left  = newNode(14);
    //root->right->right->right  = newNode(15);
  
    spiralLevelOrder(root);
  
    return 0;
}


Java




/* Java program to convert Binary Tree into Doubly Linked List 
   where the nodes are represented spirally */
  
import java.util.*;
  
// A binary tree node
class Node 
{
    int data;
    Node left, right;
  
    public Node(int data) 
    {
        this.data = data;
        left = right = null;
    }
}
  
class BinaryTree 
{
    Node root;
    Node head;
  
    /* Given a reference to a node,
       inserts the node on the front of the list. */
    void push(Node node) 
    {
        // Make right of given node as head and left as
        // NULL
        node.right = head;
        node.left = null;
  
        // change left of head node to given node
        if (head != null
            head.left = node;
              
        // move the head to point to the given node
        head = node;
    }
  
    // Function to prints contents of DLL
    void printList(Node node) 
    {
        while (node != null
        {
            System.out.print(node.data + " ");
            node = node.right;
        }
    }
  
    /* Function to print corner node at each level */
    void spiralLevelOrder(Node root) 
    {
        // Base Case
        if (root == null)
            return;
  
        // Create an empty deque for doing spiral
        // level order traversal and enqueue root
        Deque<Node> q = new LinkedList<Node>();
        q.addFirst(root);
  
        // create a stack to store Binary Tree nodes
        // to insert into DLL later
        Stack<Node> stk = new Stack<Node>();
  
        int level = 0;
        while (!q.isEmpty()) 
        {
            // nodeCount indicates number of Nodes
            // at current level.
            int nodeCount = q.size();
  
            // Dequeue all Nodes of current level and
            // Enqueue all Nodes of next level
            if ((level & 1) %2 != 0) //odd level
            {
                while (nodeCount > 0
                {
                    // dequeue node from front & push it to
                    // stack
                    Node node = q.peekFirst();
                    q.pollFirst();
                    stk.push(node);
  
                    // insert its left and right children
                    // in the back of the deque
                    if (node.left != null)
                        q.addLast(node.left);
                    if (node.right != null)
                        q.addLast(node.right);
  
                    nodeCount--;
                }
            
            else //even level
            {
                while (nodeCount > 0
                {
                    // dequeue node from the back & push it
                    // to stack
                    Node node = q.peekLast();
                    q.pollLast();
                    stk.push(node);
  
                    // inserts its right and left children
                    // in the front of the deque
                    if (node.right != null)
                        q.addFirst(node.right);
                    if (node.left != null)
                        q.addFirst(node.left);
                    nodeCount--;
                }
            }
            level++;
        }
  
        // pop all nodes from stack and
        // push them in the beginning of the list
        while (!stk.empty()) 
        {
            push(stk.peek());
            stk.pop();
        }
  
        System.out.println("Created DLL is : ");
        printList(head);
    }
  
    // Driver program to test above functions
    public static void main(String[] args) 
    {
        // Let us create binary tree as shown in above diagram
        BinaryTree tree = new BinaryTree();
        tree.root = new Node(1);
        tree.root.left = new Node(2);
        tree.root.right = new Node(3);
        tree.root.left.left = new Node(4);
        tree.root.left.right = new Node(5);
        tree.root.right.left = new Node(6);
        tree.root.right.right = new Node(7);
  
        tree.root.left.left.left = new Node(8);
        tree.root.left.left.right = new Node(9);
        tree.root.left.right.left = new Node(10);
        tree.root.left.right.right = new Node(11);
        // tree.root.right.left.left = new Node(12);
        tree.root.right.left.right = new Node(13);
        tree.root.right.right.left = new Node(14);
        // tree.root.right.right.right = new Node(15);
  
        tree.spiralLevelOrder(tree.root);
    }
}
  
// This code has been contributed by Mayank Jaiswal(mayank_24)


Python3




# Python3 program to convert Binary Tree 
# into Doubly Linked List where the nodes 
# are represented spirally.
      
# Binary tree node 
class newNode: 
  
    # Constructor to create a newNode 
    def __init__(self, data): 
        self.data = data 
        self.left = None
        self.right = None
          
""" Given a reference to the head of a list
    and a node, inserts the node on the front
    of the list. """
def push(head_ref, node):
  
    # Make right of given node as 
    # head and left as None
    node.right = (head_ref)
    node.left = None
  
    # change left of head node to
    # given node
    if ((head_ref) != None):
        (head_ref).left = node 
  
    # move the head to point to 
    # the given node
    (head_ref) = node
  
# Function to prints contents of DLL
def printList(node):
    i = 0
    while (i < len(node)):
      
        print(node[i].data, end = " ")
        i += 1
      
""" Function to print corner node at each level """
def spiralLevelOrder(root):
  
    # Base Case
    if (root == None):
        return
  
    # Create an empty deque for doing spiral
    # level order traversal and enqueue root
    q = []
    q.append(root)
  
    # create a stack to store Binary 
    # Tree nodes to insert into DLL later
    stk = []
  
    level = 0
    while (len(q)):
      
        # nodeCount indicates number of
        # Nodes at current level.
        nodeCount = len(q) 
          
        # Dequeue all Nodes of current level 
        # and Enqueue all Nodes of next level
        if (level&1): # odd level
            while (nodeCount > 0):
              
                # dequeue node from front & 
                # push it to stack
                node = q[0]
                q.pop(0)
                stk.append(node)
  
                # insert its left and right children
                # in the back of the deque
                if (node.left != None):
                    q.append(node.left)
                if (node.right != None):
                    q.append(node.right)
  
                nodeCount -= 1
              
        else:     # even level
          
            while (nodeCount > 0):
              
                # dequeue node from the back & 
                # push it to stack
                node = q[-1]
                q.pop(-1)
                stk.append(node)
  
                # inserts its right and left 
                # children in the front of 
                # the deque
                if (node.right != None):
                    q.insert(0, node.right)
                if (node.left != None):
                    q.insert(0, node.left)
                nodeCount -= 1
        level += 1
          
    # head pointer for DLL
    head = []
      
    # pop all nodes from stack and push
    # them in the beginning of the list
    while (len(stk)):
      
        head.append(stk[0])
        stk.pop(0)
  
    print("Created DLL is:")
    printList(head)
  
# Driver Code
if __name__ == '__main__':
      
    """Let us create Binary Tree as 
    shown in above example """
  
    root = newNode(1)
    root.left = newNode(2)
    root.right = newNode(3)
    root.left.left = newNode(4)
    root.left.right = newNode(5)
    root.right.left = newNode(6)
    root.right.right = newNode(7)
  
    root.left.left.left = newNode(8)
    root.left.left.right = newNode(9)
    root.left.right.left = newNode(10)
    root.left.right.right = newNode(11)
    #root.right.left.left = newNode(12)
    root.right.left.right = newNode(13)
    root.right.right.left = newNode(14)
    #root.right.right.right = newNode(15)
  
    spiralLevelOrder(root)
  
# This code is contributed
# by SHUBHAMSINGH10


C#




/* C# program to convert Binary Tree into Doubly Linked List 
where the nodes are represented spirally */
using System;
using System.Collections.Generic;
  
// A binary tree node
public class Node 
{
    public int data;
    public Node left, right;
  
    public Node(int data) 
    {
        this.data = data;
        left = right = null;
    }
}
  
public class BinaryTree 
{
    Node root;
    Node head;
  
    /* Given a reference to a node,
    inserts the node on the front of the list. */
    void push(Node node) 
    {
        // Make right of given node as head and left as
        // NULL
        node.right = head;
        node.left = null;
  
        // change left of head node to given node
        if (head != null
            head.left = node;
              
        // move the head to point to the given node
        head = node;
    }
  
    // Function to prints contents of DLL
    void printList(Node node) 
    {
        while (node != null
        {
            Console.Write(node.data + " ");
            node = node.right;
        }
    }
  
    /* Function to print corner node at each level */
    void spiralLevelOrder(Node root) 
    {
        // Base Case
        if (root == null)
            return;
  
        // Create an empty deque for doing spiral
        // level order traversal and enqueue root
        LinkedList<Node> q = new LinkedList<Node>();
        q.AddFirst(root);
  
        // create a stack to store Binary Tree nodes
        // to insert into DLL later
        Stack<Node> stk = new Stack<Node>();
  
        int level = 0;
        while (q.Count != 0) 
        {
            // nodeCount indicates number of Nodes
            // at current level.
            int nodeCount = q.Count;
  
            // Dequeue all Nodes of current level and
            // Enqueue all Nodes of next level
            if ((level & 1) % 2 != 0) //odd level
            {
                while (nodeCount > 0) 
                {
                    // dequeue node from front & push it to
                    // stack
                    Node node = q.First.Value;
                    q.RemoveFirst();
                    stk.Push(node);
  
                    // insert its left and right children
                    // in the back of the deque
                    if (node.left != null)
                        q.AddLast(node.left);
                    if (node.right != null)
                        q.AddLast(node.right);
  
                    nodeCount--;
                }
            
            else //even level
            {
                while (nodeCount > 0) 
                {
                    // dequeue node from the back & push it
                    // to stack
                    Node node = q.Last.Value;
                    q.RemoveLast();
                    stk.Push(node);
  
                    // inserts its right and left children
                    // in the front of the deque
                    if (node.right != null)
                        q.AddFirst(node.right);
                    if (node.left != null)
                        q.AddFirst(node.left);
                    nodeCount--;
                }
            }
            level++;
        }
  
        // pop all nodes from stack and
        // push them in the beginning of the list
        while (stk.Count != 0) 
        {
            push(stk.Peek());
            stk.Pop();
        }
  
        Console.WriteLine("Created DLL is : ");
        printList(head);
    }
  
    // Driver program to test above functions
    public static void Main(String[] args) 
    {
        // Let us create binary tree as shown in above diagram
        BinaryTree tree = new BinaryTree();
        tree.root = new Node(1);
        tree.root.left = new Node(2);
        tree.root.right = new Node(3);
        tree.root.left.left = new Node(4);
        tree.root.left.right = new Node(5);
        tree.root.right.left = new Node(6);
        tree.root.right.right = new Node(7);
  
        tree.root.left.left.left = new Node(8);
        tree.root.left.left.right = new Node(9);
        tree.root.left.right.left = new Node(10);
        tree.root.left.right.right = new Node(11);
        // tree.root.right.left.left = new Node(12);
        tree.root.right.left.right = new Node(13);
        tree.root.right.right.left = new Node(14);
        // tree.root.right.right.right = new Node(15);
  
        tree.spiralLevelOrder(tree.root);
    }
}
  
/* This code contributed by PrinciRaj1992 */


Javascript




<script>
   
/* Javascript program to convert Binary Tree into Doubly Linked List 
where the nodes are represented spirally */
  
// A binary tree node
class Node 
{
  constructor(data)
  {
      this.data = data;
      this.left = null;
      this.right = null;
  }
}
  
var root = null;
var head = null;
/* Given a reference to a node,
inserts the node on the front of the list. */
function push(node) 
{
    // Make right of given node as head and left as
    // NULL
    node.right = head;
    node.left = null;
    // change left of head node to given node
    if (head != null
        head.left = node;
          
    // move the head to point to the given node
    head = node;
}
// Function to prints contents of DLL
function printList(node) 
{
    while (node != null
    {
        document.write(node.data + " ");
        node = node.right;
    }
}
/* Function to print corner node at each level */
function spiralLevelOrder(root) 
{
    // Base Case
    if (root == null)
        return;
    // Create an empty deque for doing spiral
    // level order traversal and enqueue root
    var q = [];
    q.unshift(root);
    // create a stack to store Binary Tree nodes
    // to insert into DLL later
    var stk = [];
    var level = 0;
    while (q.length != 0) 
    {
        // nodeCount indicates number of Nodes
        // at current level.
        var nodeCount = q.length;
        // Dequeue all Nodes of current level and
        // Enqueue all Nodes of next level
        if ((level & 1) % 2 != 0) //odd level
        {
            while (nodeCount > 0) 
            {
                // dequeue node from front & push it to
                // stack
                var node = q[0];
                q.shift();
                stk.push(node);
                // insert its left and right children
                // in the back of the deque
                if (node.left != null)
                    q.push(node.left);
                if (node.right != null)
                    q.push(node.right);
                nodeCount--;
            }
        
        else //even level
        {
            while (nodeCount > 0) 
            {
                // dequeue node from the back & push it
                // to stack
                var node = q[q.length-1];
                q.pop();
                stk.push(node);
                // inserts its right and left children
                // in the front of the deque
                if (node.right != null)
                    q.unshift(node.right);
                if (node.left != null)
                    q.unshift(node.left);
                nodeCount--;
            }
        }
        level++;
    }
    // pop all nodes from stack and
    // push them in the beginning of the list
    while (stk.length != 0) 
    {
        push(stk[stk.length-1]);
        stk.pop();
    }
    document.write("Created DLL is :<br>");
    printList(head);
}
  
// Driver program to test above functions
// Let us create binary tree as shown in above diagram
root = new Node(1);
root.left = new Node(2);
root.right = new Node(3);
root.left.left = new Node(4);
root.left.right = new Node(5);
root.right.left = new Node(6);
root.right.right = new Node(7);
root.left.left.left = new Node(8);
root.left.left.right = new Node(9);
root.left.right.left = new Node(10);
root.left.right.right = new Node(11);
// tree.root.right.left.left = new Node(12);
root.right.left.right = new Node(13);
root.right.right.left = new Node(14);
// tree.root.right.right.right = new Node(15);
spiralLevelOrder(root);
  
// This code is contributed by itsok.
  
</script>


Output

Created DLL is:
1 2 3 7 6 5 4 8 9 10 11 13 14 

Time Complexity: O(n), as we are using a loop to traverse n times. Where n is the number of nodes in the tree.
Auxiliary Space: O(n), as we are using extra space for dequeue and stack.

 



Last Updated : 30 Jun, 2022
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