Consider the following C program segment:
char p[20];
char *s = "string" ;
int length = strlen (s);
int i;
for (i = 0; i < length; i++)
p[i] = s[length — i];
printf ( "%s" , p);
|
The output of the program is? (GATE CS 2004)
(A) gnirts
(B) gnirt
(C) string
(D) no output is printed
Answer: (D)
Explanation: Let us consider below line inside the for loop
p[i] = s[length — i];
For i = 0, p[i] will be s[6 — 0] and s[6] is ‘\0′
So p[0] becomes ‘\0’. It doesn’t matter what comes in p[1], p[2]….. as P[0] will not change for i >0. Nothing is printed if we print a string with first character ‘\0′
Quiz of this Question
Last Updated :
28 Jun, 2021
Like Article
Save Article
Share your thoughts in the comments
Please Login to comment...