What is the output of following program?
#include<stdio.h>
void swap( char *str1, char *str2)
{
char *temp = str1;
str1 = str2;
str2 = temp;
}
int main()
{
char *str1 = "Geeks" ;
char *str2 = "Quiz" ;
swap(str1, str2);
printf ( "str1 is %s, str2 is %s" , str1, str2);
return 0;
}
|
(A) str1 is Quiz, str2 is Geeks
(B) str1 is Geeks, str2 is Quiz
(C) str1 is Geeks, str2 is Geeks
(D) str1 is Quiz, str2 is Quiz
Answer: (B)
Explanation: The above swap() function doesn’t swap strings. The function just changes local pointer variables and the changes are not reflected outside the function. See following for more details.
https://www.geeksforgeeks.org/swap-strings-in-c/
Last Updated :
02 Feb, 2013
Like Article
Save Article
Share your thoughts in the comments
Please Login to comment...