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Arithmetic Aptitude 6

Question 1
Which digits should come in place of * and $ if the number 4675*2$ is divisible by both 5 & 8?
A
4, 0
B
4, 5
C
1, 0
D
8, 0
Arithmetic Aptitude 6    Number Divisibility    
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Question 1 Explanation: 
Since the given number is divisible by 5, 0 or 5 must come in place of $. But a number ending with 5 is never divisible with 8 because a divisible number must be even. Therefore 0 will replace $. If the number is divisible by 8, the number formed by last three digits must be divisible by 8. The number *20 must be divisible by 8. Among all 4 options, only placing 1 in place of * makes it divisible by 8.
Question 2
What least number must be added to 4000 to obtain a number exactly divisible by 17?
A
12
B
14
C
15
D
13
Arithmetic Aptitude 6    Number Divisibility    
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Question 2 Explanation: 
Let us divide 4000 by 17.

17) 4000 (235
       34
       ….
         60
         51
        …..
           90
           85
          …..
             5

We get 5 as remainder.
Number to be added = 17-5 = 12
Question 3
What least number must be subtracted from 5000 to get a number exactly divisible by 23?
A
10
B
2
C
7
D
9
Arithmetic Aptitude 6    Number Divisibility    
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Question 3 Explanation: 
Let us divide 5000 by 23.

23) 5000 (217
      46
      ….
        40
        23
        ….
         170
         161
         …..
            9

We get 9 as remainder.

Therefore required number to be subtracted = 9
Question 4
The largest 4 digit number exactly divisible by 5, 6 and 7 is:
A
9980
B
9870
C
9540
D
9640
Arithmetic Aptitude 6    Number Divisibility    
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Question 4 Explanation: 
The required number must be divisible by L.C.M. of 5,6 and 7.
L.C.M. of 5, 6 and 7 = 5 x 6 x 7 = 210

Let us divide 9999 by 210.

210) 9999 (47
      840
     ----
      1599
      1470
      ----
       129

Required number = 9999 – 129 = 9870
Question 5
34. What should be the next number in below series? 3, 8, 15, 24, 35……..
A
44
B
47
C
48
D
49
Arithmetic Aptitude 6    Number Divisibility    
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Question 5 Explanation: 
Pattern is (22- 1), (32- – 1), (42- – 1), (52- – 1), ....

Next number will be = 72- – 1 = 49 – 1 = 48
Question 6
The average of 21 results is 20. Average of 1st 10 of them is 24 that of last 10 is 14. the result of 11'th is :
A
42
B
44
C
46
D
40
Arithmetic Aptitude 6    Numbers    
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Question 6 Explanation: 
 11'th result = sum of 21 results – sum of 20 results
             = 21 x 20 – (24 x 10 + 14 x 10)
             = 420 – (240 + 140)
             = 420- 380 = 40
There are 6 questions to complete.
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