## Arithmetic Aptitude 2

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Question 1 |

512 x 512 + 488 x 488 = ?

512438 | |

502568 | |

500288 | |

514318 |

**Arithmetic Aptitude 2**

**Simplification and Approximation**

**Discuss it**

Question 1 Explanation:

X^{2}+ Y^{2}= 1/2[(X + Y)^{2}+ (X – Y)^{2}] 5122 + 4882 = ½ [(512+488)^{2}+ (512-488)^{2}] = 1/2[10002+242] = 1/2(1000000+576) = 500288

Question 2 |

The sum of all 3 digit numbers divisible by 3 is:

165150 | |

164380 | |

168420 | |

165250 |

**Arithmetic Aptitude 2**

**Number Divisibility**

**Discuss it**

Question 2 Explanation:

All 3 digit numbers divisible by 3 are : 102, 105, 108, 111, ..., 999. This is an A.P. with first element 'a' as 102 and difference 'd' as 3. Let it contains n terms. Then, 102 + (n - 1) x 3 = 999 102 + 3n-3 = 999 3n = 900 or n = 300 Sum of AP = n/2 [2*a + (n-1)*d] Required sum = 300/2[2*102 + 299*3] = 165150.

Question 3 |

Which of Following is not divisible from 4 ?

546702 | |

556824 | |

367312 | |

467536 |

**Arithmetic Aptitude 2**

**Number Divisibility**

**Discuss it**

Question 3 Explanation:

**If last 2 digits are divisible by 4, then number is also divisible by 4.**

In case of 546702 last 2 digits are 02 (x) In case of 556824 last 2 digits are 24 (/) In case of 367312 last 2 digits are 12 (/) In case of 467536 last 2 digits are 36 (/)

Question 4 |

What should be the value of * in 985*865, if number is divisible by 9?

6 | |

5 | |

4 | |

0 |

**Arithmetic Aptitude 2**

**Number Divisibility**

**Discuss it**

Question 4 Explanation:

If a number is divisible by 9, the sum of digits is also divisible by 9

9 + 8 + 5 + * + 8 + 6 + 5 = 9x 41 + * = 9x Nearest value of 9x must be 45 41 + * = 45 * = 4

Question 5 |

The least perfect square, which is divisible by each of 15, 20 and 36 is:

1200 | |

800 | |

1000 | |

900 |

**Arithmetic Aptitude 2**

**Number Divisibility**

**Discuss it**

Question 5 Explanation:

LCM of 15, 20 and 36 is 180 Now 180 = 3 x 3 x 2 x 2 x 5 To make it perfect square, it must be multiplied from 5. So required no. = 32 x 22 x 52 = 900

Question 6 |

What should be the value of x in equation (x / √216) = (√96 / x)

12 | |

13 | |

9 | |

11 |

**Arithmetic Aptitude 2**

**Simplification and Approximation**

**Discuss it**

Question 6 Explanation:

Let (x / √216) = (√96 / x) Then x^{2}= √(216 x 96) = √(36 x 2 x 3 x 16 x 2 x 3) = √(6^{2}x 4^{2}x 2^{2}x 3^{2}) = 6 x 4 x 2 x 3 = 144 Or x = 12

Question 7 |

Sum of 4 childeren born at interval of 4 years is is 36. What is the age of youngest child?

2 years | |

3 years | |

4 years | |

5 years |

**Arithmetic Aptitude 2**

**Age**

**Discuss it**

Question 7 Explanation:

Let the ages of children be x, (x+4), (x+8) and (x+12) years. Then x + x + 4 + x + 8 + x +12 = 36 4x + 24 = 36 4x = 12 x = 3 Age of the youngest child = x = 3 years

Question 8 |

A is 5 years older than B who is thrice as old as C. If the total of ages of A, B and C is 40, then how old is C ?

6 | |

7 | |

5 | |

8 |

**Arithmetic Aptitude 2**

**Age**

**Discuss it**

Question 8 Explanation:

Let C’s age be x years then B’s age be 3x years and A’s age be (3x+5) years Therefore x + 3x + (3x + 5) = 40 7x + 5 = 40 7x = 35 x = 5

There are 8 questions to complete.